the average ( arithmetic mean) of 5 positive integers is 350. Two of the integers are 99 and 102 and the other integers are greater than 102. If all 5 integers are different, what is the greatest possible value for any of the 5 integers ?

Question

anonymous · Answer

1342. Because two of the integers are given, we must find the minimum possible values of the other two integers, and find the maximum value of the third. Given the rules, the four possible minimum values are 99, 102, 103, and 104. Solve for x in the following equation:
(99 + 102 + 103 + 104 + x)/5 = 350
x = 1342

anonymous · Answer

Please let me know if any part of it doesn't make sense.