Question

If spine bone density is normally distributed in young women with a mean of 1.0 g/cm2 and a standard deviation of .10 g/cm2, then how many young women out of 100 would you expect to have bone densities greater than 1.15 g/cm2?

Answer 1

\[z=\frac{x-mean}{sd}\]

Answer 2

15/10 = 1.50 for a ztable look up

Answer 3

Ah - Over sd. Thank you!

Answer 4

yep

Answer 5

do you have a normal cdf function? or do you have to resort to a ztable?

Answer 6

.0668 from z table?

Answer 7

(z table)

Answer 8

.9332

Answer 9

ztables tend to be author specific in format :/

for a left tail at -1.5 i have .0668; out of 100 is just 6.68% above the +1.5