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If you deposit $1000 in a savings account with an interest rate of r compounded annually, then the balance in the account after 3 years is given by the function B(c) = 1000(1 + r)3, where r is written as a decimal. What interest rate will yield a balance of $1100 after 3 years? a. 3.23% c. 3.63% b. 3.33% d. 3.66%
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help me out please!
The amount in the savings account is given by the function. So, we just set $1100 equal to the equation and solve for r: \[1100=1000(1+r)^3\]Divide both sides by 1000: \[1.1=(1+r)^3\]Cube root both sides: \[1.03228=1+r\]Subtract r from both sides: \[r=.03228\]
thanks!
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