Solve 2x2 - 8x = -7.
I just want to know if my answer is correct. I got x=2+- 2 sqr 2

Question

Solve 2x2 - 8x = -7.
I just want to know if my answer is correct. I got x=2+- 2 sqr 2

swissgirl · Answer

$2x^2-8x+7=0$

$A=2, B=-8, C=7$

$\large \frac{-(-8) \pm \sqrt{(-8)^2-4(2)(7)}}{2(2)}$ 

$\large \frac{8 \pm \sqrt{64-56}}{4}$ 

$\large \frac{8 \pm \sqrt{8}}{4}$ 

$\large \frac{8 \pm 2\sqrt{2}}{4}$ 

$\large \frac{4\pm \sqrt{2}}{2}$ 

OR $\large 2\frac{\pm \sqrt{2}}{2}$

swissgirl · Answer

hmmm are you sure this is the right equation?

anonymous · Answer

oh sorry these are the answer choices:
 negative 2 plus or minus square root of 2 
 negative 2 plus or minus 2 square root of 2 
 quantity of 2 plus or minus square root of 2 all over 2 
 2 plus or minus square root of 2 end root over 2

swissgirl · Answer

So what do you think?

anonymous · Answer

im not sure I cant understand what you typed up there..haha

swissgirl · Answer

So how did you get your answer?

anonymous · Answer

my own answer is x=2+-2 sqr 2

swissgirl · Answer

How did you get that?

anonymous · Answer

its long in my notebook haha I just need to know if my answer is correct or not

swissgirl · Answer

Your answer is incorrect

swissgirl · Answer

Look at my answer above

anonymous · Answer

OH it shows now! thanks! ill review it and find my mistake!

swissgirl · Answer

$ \large 2 \pm \frac{\sqrt{2}}{2}$

anonymous · Answer

Thanks!