Which of the following is a factor of 6x^2 + 2x – 21? explain?
if it factors nicely ..... multiply the first and last coeffs; what do we get?
-126?
and if we create a factor list of -126, we could find 2 factors that add to 2
none?
then this wont factor nicely into rational numbers
so is it prime?
its not prime, its just not rational ... itll contain a square root in it
ok so what do i put for an answer?
6x^2 + 2x – 21 = 0 6x^2 + 2x = 21 6(x^2 + 1/3x) = 21 6(x^2 + 1/3x + 1/36 - 1/36) = 21 6 (x+1/6)^2 - 6/36 = 21 6 (x+1/6)^2 = 21 + 1/6 (x+1/6)^2 = (21(6)+ 1)/36 x+1/6 = +- sqrt(127)/6 x =[-1 +- sqrt(127)]/6
well considering it says "which of the following"; im not even sure what the options would be ...
4x – 3 2x + 7 6x – 3 None of the above
lol, then i know what id pick ....
it doesnt factor nicely into rationals; and they give you 3 nice rational options
so is it none of the above
im going with none of the above, yes
thank you for explaining and not just giving an answer
its what i do best ... even when im trying to just give an answer lol
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