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Mathematics 15 Online
OpenStudy (anonymous):

-(6p+12)

OpenStudy (anonymous):

-(6p+12) -1(6p+12)

OpenStudy (anonymous):

-1*6p = ___ -1*12 = ___

OpenStudy (anonymous):

-6p-12?

OpenStudy (anonymous):

-(6p+12) -1(6p+12) -6p - 12

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

what about -3x+9/-3

OpenStudy (anonymous):

\[ \frac{ -3x + 9 }{ -3 }\]

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

Okay. Do you know how to start? Any idea?

OpenStudy (anonymous):

not really haha

OpenStudy (anonymous):

divide each everything by -3?

OpenStudy (anonymous):

You want to simplify, right?

OpenStudy (anonymous):

yes so wouldnt it be x-3?

OpenStudy (anonymous):

Yeah divide everything by -3.

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

last one! -3(d-3)+5d

OpenStudy (anonymous):

What do you think you should do first?

OpenStudy (anonymous):

i think you would distribute -3 to the d and 3

OpenStudy (anonymous):

Distribute the -3 to everything in the parenthesis, first.

OpenStudy (anonymous):

So yah, good.

OpenStudy (anonymous):

so know it looks like (-3d+9)+5d

OpenStudy (anonymous):

-3(d-3)+5d -3d + 9 + 5d

OpenStudy (anonymous):

You dont need the ( ) any more.

OpenStudy (anonymous):

ok so then hmmm

OpenStudy (anonymous):

-3(d-3)+5d -3d + 9 + 5d then: -3d + 5d = ___

OpenStudy (anonymous):

9?

OpenStudy (anonymous):

oh! so it would be 2d+9?

OpenStudy (anonymous):

-3(d-3)+5d -3d + 9 + 5d then: -3d + 5d = 2d So: 2d + 9

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

thxs! :)

OpenStudy (anonymous):

yw :) {BEST RESPONSE} Thank you :)

OpenStudy (anonymous):

one more? haha

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

SORRY I GTG

OpenStudy (anonymous):

:(

OpenStudy (anonymous):

but open a new question and post ur question. there are more users who will help :)

OpenStudy (anonymous):

because you closed this question, so other users wont come here, well since its closed. lol

OpenStudy (anonymous):

Identify which property problem below would help you solve the following scenario: your math class has 32 students. you would like to treat the class to cookies. you would like each person to have 5 cookies. which expression would be would be a quic way to figure out how many cookies you would need?

OpenStudy (anonymous):

ok! :) thanks

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