Question

h

Answer 1

Start with y=ax^2 + bx + c

Answer 2

well the easy way to do this is to set up the equation using the x intercepts

\[y = a(x + 3)(x -1)\]

where a is a constant

distributing gives

\[y = a(x^2 + 2x -3) \]

now substitute the values from the y intercept, x = 0 and y = 2 to find the value of the constant a.

then just distribute and you'll have a quadratic meeting the given conditions.