PLEASE HELP QUICKLYYY

Divide:

(6x) / (12y) divided by (4x^5) / (3y^3)

so far i flipped them to multiply, but idk where to go from here

Question

PLEASE HELP QUICKLYYY

Divide:

(6x) / (12y) divided by (4x^5) / (3y^3)

so far i flipped them to multiply, but idk where to go from here

campbell_st · Answer

well the rule for dividing fractions is flip the 2nd fraction and multiply

$$\frac{6x}{12y} \times \frac{3y^3}{4x^5}$$

which becomes 

$$\frac{6 \times 3 \times x \times y^3}{12 \times 4 \times x^5 \times y}$$

eliminate common factors for the answer

anonymous · Answer

i have the answer, i just don't understand how to get to it...
the answer is (3y^2) / (8x^4)
i see how it becomes x^4 and y^2... but why is it 3 and 8?

campbell_st · Answer

ok... look at the numbers 1st 

what does 18/48 simplify to...? hint divide them both by 6

anonymous · Answer

ohhhh. i wasn't multiplying the numbers first, i was dividing.. 
I understand now, i see what i did wrong.

anonymous · Answer

Thank you so much!