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Find the value of x so that the line passing through the points will have the given slope: (x, 6) and (10, -3) with a slope of -3/2.
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You can use the slope formula for "m":\[m = \frac{ y _{2} - y _{1} }{ x _{2} - x _{1} }\]where you are given points:\[(x _{1}, y _{1})\]and\[(x _{2}, y _{2})\]
\[\frac{ -3 }{ 2 } = \frac{ 6 - (-3) }{ x - 10 }\]Can you solve it from here or do you need more help?
I think I can handle it; thank you very much for the help! :)
uw!
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