Mathematics
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OpenStudy (anonymous):
x+2=√(x-4) solve for x.
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OpenStudy (anonymous):
square both sides and then simplify, you should end up with a quadratic
OpenStudy (anonymous):
1) Squaring both sides:
(x+2)^2 = (x-4)
2) Expanding (x+2)^2
(x^2) + (4x) + 4 = (x-4)
3) Simplifying the expression:
(x^2) + (4x-x) + (4+4) = 0
(x^2) + 3x + 8 = 0
4) Solving for x = ?
OpenStudy (anonymous):
so my final answer would be x^2+3x+8 rite?
OpenStudy (anonymous):
Not quite
OpenStudy (anonymous):
wait y not?
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OpenStudy (anonymous):
it said solve for x...so find solutions for x that satisfy that equation
OpenStudy (anonymous):
The directions say to solve for x
Which should look like this:
x=...
OpenStudy (anonymous):
oh yeah
OpenStudy (anonymous):
seems you will get complex roots.
OpenStudy (anonymous):
oh like w/ imaginary #'s?
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OpenStudy (anonymous):
yea imaginary number
OpenStudy (anonymous):
try using the quadratic formula
OpenStudy (anonymous):
ugh! but that's not really an option
OpenStudy (anonymous):
ok i'll try
OpenStudy (anonymous):
did you copy the question down correctly?
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OpenStudy (anonymous):
yea
OpenStudy (anonymous):
it was exactly:
x+2=√(4-x)
OpenStudy (anonymous):
4-X not X-4
OpenStudy (anonymous):
yes isn't that what I said??
OpenStudy (anonymous):
nope
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OpenStudy (anonymous):
oops sorry
OpenStudy (anonymous):
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