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Mathematics 17 Online
OpenStudy (anonymous):

Medal + Fan

OpenStudy (anonymous):

OpenStudy (anonymous):

http://www.mathopenref.com/kiteperimeter.html

OpenStudy (anonymous):

do u need the answer or does this explain it?

OpenStudy (anonymous):

i want to learn how to do it

OpenStudy (anonymous):

Perimeter of Kite = 2(a + b) a^2 = 24^2 + 7^2 b^2 = 7^2 + 4^2

OpenStudy (anonymous):

okay, well this is geometry right? so you need to understand the use of sin, cos, and tan, do u get that? you can also solve it by using this formula. its easier and faster. Add the diagonals and times by 2

OpenStudy (anonymous):

did u understand the formula or do u want to do it the harder way using cos, sin, tan?

OpenStudy (anonymous):

2(7+4) right @robinnicole218

OpenStudy (anonymous):

Perimeter of Kite = 2(a + b) a^2 = 24^2 + 7^2 A = 25 b^2 = 7^2 + 4^2 B= sqrt 65 Perimeter = 2(a+b) = 2(25+sqrt65) =~~66.1

OpenStudy (sasogeek):

there's a theory called the pythagoras theorem, read about it here to understand @dauspex answer http://en.wikipedia.org/wiki/Pythagorean_theorem @dauspex next time please add some explanation to your answers :) thanks

OpenStudy (anonymous):

perimeter = 2a+2b where: a is the length of each side in one pair b is the length of each side in the other pair

OpenStudy (anonymous):

can you help me with this one to

OpenStudy (anonymous):

kite have two angle that add up to 180. u are given two other angles.. follow this...

OpenStudy (anonymous):

attching a pic

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

tell me if u understand so far, im not done tho

OpenStudy (anonymous):

i understand so far

OpenStudy (anonymous):

these are properties of kites: •Two pairs of adjacent sides of a kite are equal in length •One pair of opposite angles (the ones that are between the sides of unequal length) are equal in size. •One diagonal bisects the other. •Diagonals intersect at right angles.

OpenStudy (anonymous):

look at this now

OpenStudy (anonymous):

i think i got the answer

OpenStudy (anonymous):

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