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h(x)=2x-5/3 find it inverse function
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is that \[h(x)=2x-\frac53\] or\[h(x)=\frac{2x-5}3\]
in either case solve the equation for x, Then switch x for h and h for x, done.
\[h(x)=\frac{ 2x-5 }{ 3 }\]
so can you solve it for x=? (multiply both sides by 3, add 5 to both sides, then divide both sides by 2)
wait
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do i have to change the h(x) into y?
you can if you like
if you were going to do that you should make it the first step,
\[h(x)=\frac{ 3x+5 }{ 2 }\] in this the answer?
is this the answer? sorry wrong grammar
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yeah that's the inverse
good work
thanks !
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