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What inequality is graphed?. y < |x – 2| – 1 y < –|x – 2| – 1 y < |x + 2| – 1 y < –|x + 2| – 1
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for big x (positive or negative), |x-2| and |x+2| will be both big. Since the area is below the turned to the negative side, there must be a '-' sign in front of the absolute value.
It's y < –|x – 2| – 1 or y < –|x + 2| – 1. Find among those two the one that has its peak at x=-2. (we see on the graph it's at this point)
is it B?
it's D. when you look at the graph of f(x) and f(x-a), the one of \(f(x-a)\) is shifted to the right of the quantity \(a\). |x+2| = |x-(-2)|. <- this one is shifted to the right by a quantity "-2". so it's to the left by quantity 2.
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y<-|x+2|-1|dw:1373561383229:dw|
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