Question

Let sin(X)=16 then:
A) x=Cos^-1 (.16)
B) x= Cos^-1 (.99)
C) X= Sin .99
D) x=-sin .16

Answer 1

Thinking it would be D) x=-sin .16 not sure?

Answer 2

if sinx = .16 and not 16; yes

Answer 3

Sin X is 16 not .16

Answer 4

so would it be A) instead x=cos^-1 (.16)

Answer 5

x does not exist in that case.

-1 ≤ sinx ≤ 1

Answer 6

I don't know how to find it

Answer 7

you can't. the range of sinx is [-1,1]

sinx cant = 16. check the question again

Answer 8

you are right
let sin (X) = .16

Answer 9

x=-sin.16

Answer 10

x = sin^(-1) .16 - not an option

Answer 11

no

Answer 12

none are right

Answer 13

I did have the problem wrote wrong it was sin x = .16