Find the roots of the polynomial equation.

x^3 - 2x^2 + 10x + 136 = 0

A. –3 ± 5i, –4

B. 3 ± 5i, –4

C. –3 ± i, 4

D. 3 ± i, 4

Question

Find the roots of the polynomial equation.

x^3 - 2x^2 + 10x + 136 = 0

A. –3 ± 5i, –4	

B. 3 ± 5i, –4	

C. –3 ± i, 4	

D. 3 ± i, 4

jdoe0001 · Answer

have you covered using the "rational root test"?

explainitlikeimfive · Answer

No

jdoe0001 · Answer

have you .... done polynomials long division? 
or even synthetic division?
because you'll need it for the "rational root test"

explainitlikeimfive · Answer

Neither one

explainitlikeimfive · Answer

I dont have rational root test. Its not in my curriculum.

jdoe0001 · Answer

well, is how to find roots off a polynomials

jdoe0001 · Answer

so, if it isn't in the syllabus,  how are you expected to find them?

explainitlikeimfive · Answer

I have no idea.

jdoe0001 · Answer

Ms Cleo got busted already, so, she won't work Ms Cleo, lady on tv with fake jamaican accent reading palms and doing the tarot http://i1.ytimg.com/vi/pWyHiV3l3MA/hqdefault.jpg <-

explainitlikeimfive · Answer

I think you misplaced your comment there buddy.

jdoe0001 · Answer

hehe

jdoe0001 · Answer

well, for synthetic division, is rather simple -> http://www.youtube.com/watch?v=bZoMz1Cy1T4 and rational root tests http://www.youtube.com/watch?v=GTx-rXTQg1o

jdoe0001 · Answer

the rational root test, gives you possible root combinations, try a likely one or several ones, divide the polynomial, if the remainder is 0, then is a root :)