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b^2 -4ac>0 means the root is real, True or false?
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true, since the radical is not negative
Look up what b^2-4ac (the discriminant) means
robz, can you tell us why we have to take a radical though?
Just trying to get her to learn.
because the quadratic equation has b^2 -4ac under the radical
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Thanks guys(:
can't take the square root of a negative number without complex numbers
robz8, that is correct, but do you know why the quadratic equation has b^2-4ac under the radical?
|dw:1373589012648:dw|
haha do you want me to proof the quadratic equation?
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I know that radicals can't be negitive.
well they can, but their result would be complex numbers, making them imaginary
Well thats why they wouldn't be real then.
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