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Mathematics 10 Online
OpenStudy (anonymous):

b^2 -4ac>0 means the root is real, True or false?

OpenStudy (anonymous):

true, since the radical is not negative

OpenStudy (bahrom7893):

Look up what b^2-4ac (the discriminant) means

OpenStudy (bahrom7893):

robz, can you tell us why we have to take a radical though?

OpenStudy (bahrom7893):

Just trying to get her to learn.

OpenStudy (anonymous):

because the quadratic equation has b^2 -4ac under the radical

OpenStudy (anonymous):

Thanks guys(:

OpenStudy (anonymous):

can't take the square root of a negative number without complex numbers

OpenStudy (bahrom7893):

robz8, that is correct, but do you know why the quadratic equation has b^2-4ac under the radical?

OpenStudy (primeralph):

|dw:1373589012648:dw|

OpenStudy (anonymous):

haha do you want me to proof the quadratic equation?

OpenStudy (anonymous):

I know that radicals can't be negitive.

OpenStudy (anonymous):

well they can, but their result would be complex numbers, making them imaginary

OpenStudy (anonymous):

Well thats why they wouldn't be real then.

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