A ladder 12 feet long leans against a tree trunk. The angle from the ground to the ladder is 36°. How far is the base of the ladder from the base of the tree?
@Red_Stevens Trig stuff huh... It helps if you draw a diagram :) |dw:1373604121773:dw|
|dw:1373604140050:dw|
So... let's put the known values up... The ladder is 12 feet long so...|dw:1373604190184:dw|
So what do you do from here? |dw:1373604211678:dw|
Oh noes D: The angle \(36^o\) is made by the |dw:1373604283298:dw| to the ground, here:|dw:1373604302013:dw| So the angle goes here:|dw:1373604320409:dw|
Oh, so what do you do from there?
You know the trigonometric stuff... sine, cosine, etc?
Not really, I'm jumping up a grade and I'm trying to get caught up with some stuff. I know the basics though.
You know sines, cosines... as in SOH-CAH-TOA \[\Large \sin\theta = \frac{opposite}{hypotenuse}\]\[\Large \cos\theta = \frac{adjacent}{hypotenuse}\]\[\Large \tan\theta =\frac{opposite}{adjacent}\]
Okay, so which one would I choose for this equation.
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