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why would you use the points (3,-4) and (-1,-8) to determine the average rate of change of the function g(x)=-x²+3x-4 on the interval -1≤x≤3
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what is the value of g(-1)? and of g(3)? (-1, g(-1)) and (3,g(3)) are the endpoints
\[avg=\frac{g(3)-g(-1)}{3-1}\] its just the slope formula
when i do g(3) i get -7 ? :S
wait nvm
adding and multiplying .... the bane of math :)
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i keep making careless mistakes today :(
thanks for the help @amistre64
this time i go g(3)=-4 and g(-1)=-8
got*
youre welcome, and we all keep making careless mistakes ... its just the way the pencil pushes
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