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3x^2+s=11-x^2 my options (+-3/2) (+-squareroot3) ()
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\[\pm3/2 ,+\sqrt{3}, ()\]
+s??????
What?
Oh the second one is also a +_ one.
what is that "s" in the very first equation ?
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Hahah, It's suppose to be a 2. My bad.
get the x^2 terms in one side and the numerical terms in the other..
4x^2=9?
well...now divide both sides by 4 and square root it
Got it, Thank you(:
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u r welcome..:) put a plus minus sign(\(\pm \) )before your answer...
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