parallel lines question.... I don't know where to start!
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OpenStudy (anonymous):
OpenStudy (amistre64):
when x=0, y=?
when y=0, x=?
OpenStudy (anonymous):
how will that help?
OpenStudy (amistre64):
only one set of equations will fit the results
OpenStudy (amistre64):
|dw:1373647642588:dw|
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OpenStudy (amistre64):
when x=0, you are left with:
By = C
or y = C/B
OpenStudy (amistre64):
6y = 12, when y=12/6
2y = 12 when y=12/2
-6y = 12, when y=-12/6
-2y = 12 when y=-12/2
OpenStudy (amistre64):
since the y values at x=0 on the graphs are not negative .... we want a +6 and a +2
OpenStudy (anonymous):
I don't follow your logic
OpenStudy (amistre64):
then you might want to review how to read a graph ....
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OpenStudy (amistre64):
for a given standard line equation:
Ax + By = C
the y intercept is determine when x=0
A(0) + By = C
or By = C
the y intercept is therefore y = C/B
OpenStudy (amistre64):
out of all your options .... you have
+6y = 12
+2y = 6
-6y = 12
-2y = 6
when we look on the graph at x=0, we see that the value of y are far above, and positive; therefore the y intercepts are positive numbers
+6y = 12
+2y = 6
have to be the ends of the solutions
OpenStudy (anonymous):
oooooh! so its A?
OpenStudy (amistre64):
yes, its A :)
OpenStudy (anonymous):
okay thank you :)
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