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Mathematics 4 Online
OpenStudy (anonymous):

parallel lines question.... I don't know where to start!

OpenStudy (anonymous):

OpenStudy (amistre64):

when x=0, y=? when y=0, x=?

OpenStudy (anonymous):

how will that help?

OpenStudy (amistre64):

only one set of equations will fit the results

OpenStudy (amistre64):

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OpenStudy (amistre64):

when x=0, you are left with: By = C or y = C/B

OpenStudy (amistre64):

6y = 12, when y=12/6 2y = 12 when y=12/2 -6y = 12, when y=-12/6 -2y = 12 when y=-12/2

OpenStudy (amistre64):

since the y values at x=0 on the graphs are not negative .... we want a +6 and a +2

OpenStudy (anonymous):

I don't follow your logic

OpenStudy (amistre64):

then you might want to review how to read a graph ....

OpenStudy (amistre64):

for a given standard line equation: Ax + By = C the y intercept is determine when x=0 A(0) + By = C or By = C the y intercept is therefore y = C/B

OpenStudy (amistre64):

out of all your options .... you have +6y = 12 +2y = 6 -6y = 12 -2y = 6 when we look on the graph at x=0, we see that the value of y are far above, and positive; therefore the y intercepts are positive numbers +6y = 12 +2y = 6 have to be the ends of the solutions

OpenStudy (anonymous):

oooooh! so its A?

OpenStudy (amistre64):

yes, its A :)

OpenStudy (anonymous):

okay thank you :)

OpenStudy (amistre64):

youre welcome

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