Question

Write the equation of the line that passes through (2,2) and (6,3) in standard form

Answer 1

use \[(y-y1)=m(x-x1)\]
m=\[(y2-y1)\div(x2-x1)\]
use y1 and x1 must be the same coordinate, my suggestion is use (2,2)
y2 is 4 and x2 is 6

Answer 2

I need the actual answer

Answer 3

y-2=\[y-2=(1\div4) \times (x-2)\]
y=\[(1\div4)x -(5\div2)\]

Answer 4

no its +3/2 instead of -5/2

Answer 5

The choices are 4x+4y=6
x+4y=12
4x+4y=12
4x+4y=-12
x-4y=-6

Answer 6

we cant give answers

Answer 7

we r here to help not solve

Answer 8

stuff2do gave u the answer basssically, all u have to do is plug in the numbers