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HELP!!! VERY URGENT!!! Find the derivative of f(x) = (x^2 - 4x)(√x - 1).
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\[(x^2 - 4x)(\sqrt{x - 1} )\] is is your question?
The √x is by itself.
http://www.wolframalpha.com/input/?i=derive+%28x%5E2+-+4x%29*%28sqrt%28x%29+-+1%29
\[\left( x^{2}-4 \right)\left( \sqrt{x}-1 \right)\]
4x
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(5/2)x^(3/2) - 2x - 6x^(1/2) + 4
\[\frac{ 5 }{ 2 }x ^{\frac{ 3 }{2 }} - 2x - 6\sqrt{x} + 4\]
$$\bf \left( x^{2}-4 \right)\left( \sqrt{x}-1 \right)\\ \implies \left( x^{2}-4 \right)\left( x^{\frac{1}{2}}-1 \right) $$ then use the product rule
Could the answer also be , \[\sqrt{x}\left( \frac{ 5}{ 2}x - 6\right)-2x+4\]
|dw:1373668884758:dw|
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