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Mathematics 17 Online
OpenStudy (anonymous):

true or false? the domain of F(x)= log(small b)x is the set of all positive real numbers.

ganeshie8 (ganeshie8):

domain of log x is x > 0 so false

OpenStudy (anonymous):

& this one: what is the x-intercept of the function below? F(x)=log(small 7)(x-1)

OpenStudy (anonymous):

I got (2,0)

ganeshie8 (ganeshie8):

x intercept of log(x) is (1, 0) log(x-1) is translated right side by 1 unit so, its x-intercept wud be (2, 0)

ganeshie8 (ganeshie8):

you're right, good work :)

OpenStudy (anonymous):

thanks. ok & this one: F(x)=log(small 7)x What is the domain?

ganeshie8 (ganeshie8):

log x domain = x >0

OpenStudy (anonymous):

log7x u mean right?

ganeshie8 (ganeshie8):

base doesnt matter, it can be any positive number log(small b)x domain is always x >0

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

& this: F(x)=log(small0.725) the domain and range,

OpenStudy (anonymous):

well I guess we already know that domain is x>0

OpenStudy (anonymous):

but range I need help w/

ganeshie8 (ganeshie8):

y=log(small b)x domain : x > 0 range : all real numbers

OpenStudy (anonymous):

or is domain not x>0

OpenStudy (anonymous):

ok nvm

ganeshie8 (ganeshie8):

b > 0, you need to remember the logx curve, and try to visualize how other graphs form, thats all

OpenStudy (anonymous):

I thought that was only if b>1 not b>0 ??

ganeshie8 (ganeshie8):

let me think a bit

ganeshie8 (ganeshie8):

lets consider \(y = a^x\) its range is the domain of \(y = log_a x\)

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

& what abt this: true or false. the range of F(x)=log(smallb)x is the set of all positive real numbers.

OpenStudy (anonymous):

sorry hold on

ganeshie8 (ganeshie8):

lets analyze the case 0< a < 1

OpenStudy (anonymous):

for this problem wouldn't it be all real numbers not just positive real numbers??

ganeshie8 (ganeshie8):

yes, so its false

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

then this: what is the domain? F(x)= 2+log(small 0.6)x

OpenStudy (anonymous):

it would be x>0 correct?

ganeshie8 (ganeshie8):

no translation in x side, oly a shrink in hte graph so, domain wont change from the regular x > 0

OpenStudy (anonymous):

k

OpenStudy (anonymous):

then: what is the x-intercept of F(x)=log(small 0.25)x

OpenStudy (anonymous):

I got 1, something

OpenStudy (anonymous):

I think. (1,0)/ or it could be 1, something else

ganeshie8 (ganeshie8):

x-intercept is a point on x so it will be of form (k, 0)

OpenStudy (anonymous):

ok so then (1,0

ganeshie8 (ganeshie8):

(1, 0) = \(\checkmark\)

OpenStudy (anonymous):

ok and then: true or false. The function F(x)= log(small3)x is decreasing

ganeshie8 (ganeshie8):

remember this :- \(y = \log_b x\) if b > 1, function is increasing i b is between 0 and 1, function is decreasing

ganeshie8 (ganeshie8):

*if

OpenStudy (anonymous):

so its increasing wow idk why I just asked u that. its like @ the very bottom of my notes

ganeshie8 (ganeshie8):

good u have a notes :)

OpenStudy (anonymous):

yea

ganeshie8 (ganeshie8):

one thing about ur original FIRST question

ganeshie8 (ganeshie8):

true or false? the domain of F(x)= log(small b)x is the set of all positive real numbers.

ganeshie8 (ganeshie8):

thats ur first question, right ?

OpenStudy (anonymous):

yea why?

ganeshie8 (ganeshie8):

domain of log x is x > 0 so false

OpenStudy (anonymous):

I think u said that already

ganeshie8 (ganeshie8):

i had a typo there, i meant to type below :- domain of log x is x > 0 so true

OpenStudy (anonymous):

is the x- intercept of F(x)= log(small 2)x (1,0) ??

OpenStudy (anonymous):

wait r u serious????????????

OpenStudy (anonymous):

noooooo I missed that one!!!!!

ganeshie8 (ganeshie8):

yes ! x > 0 means, its all positive numbers. so its true

ganeshie8 (ganeshie8):

u doing flvs ?

OpenStudy (anonymous):

:( :(

ganeshie8 (ganeshie8):

giving exam is it ?

OpenStudy (anonymous):

no, it was a mini 3 question quiz w/ notes but it was stage 2. where u can go back and change things :)

OpenStudy (anonymous):

so I missed it :(

ganeshie8 (ganeshie8):

ohk sorry about that

OpenStudy (anonymous):

so is the answer to my latest question correct? :( :( ○○○○

OpenStudy (anonymous):

it's ok..

ganeshie8 (ganeshie8):

correct

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

oh great

OpenStudy (anonymous):

Im entering this new unit..... and I think it's proofs :(

ganeshie8 (ganeshie8):

this is algebra or geometry ?

OpenStudy (anonymous):

algebra ii

OpenStudy (anonymous):

sorry I think I said proofs instead of "proof" the term

OpenStudy (anonymous):

:p

ganeshie8 (ganeshie8):

okie :) good luck !!!

OpenStudy (anonymous):

thanks so much!!! :)

ganeshie8 (ganeshie8):

np :)

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