Mathematics
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OpenStudy (anonymous):
true or false?
the domain of F(x)= log(small b)x is the set of all positive real numbers.
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ganeshie8 (ganeshie8):
domain of log x is x > 0
so false
OpenStudy (anonymous):
& this one:
what is the x-intercept of the function below?
F(x)=log(small 7)(x-1)
OpenStudy (anonymous):
I got (2,0)
ganeshie8 (ganeshie8):
x intercept of log(x) is (1, 0)
log(x-1) is translated right side by 1 unit
so, its x-intercept wud be (2, 0)
ganeshie8 (ganeshie8):
you're right, good work :)
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OpenStudy (anonymous):
thanks. ok & this one:
F(x)=log(small 7)x
What is the domain?
ganeshie8 (ganeshie8):
log x domain = x >0
OpenStudy (anonymous):
log7x u mean right?
ganeshie8 (ganeshie8):
base doesnt matter, it can be any positive number
log(small b)x domain is always x >0
OpenStudy (anonymous):
oh ok
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OpenStudy (anonymous):
& this:
F(x)=log(small0.725) the domain and range,
OpenStudy (anonymous):
well I guess we already know that domain is x>0
OpenStudy (anonymous):
but range I need help w/
ganeshie8 (ganeshie8):
y=log(small b)x
domain : x > 0
range : all real numbers
OpenStudy (anonymous):
or is domain not x>0
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OpenStudy (anonymous):
ok nvm
ganeshie8 (ganeshie8):
b > 0, you need to remember the logx curve, and try to visualize how other graphs form, thats all
OpenStudy (anonymous):
I thought that was only if b>1 not b>0 ??
ganeshie8 (ganeshie8):
let me think a bit
ganeshie8 (ganeshie8):
lets consider
\(y = a^x\)
its range is the domain of \(y = log_a x\)
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
& what abt this:
true or false.
the range of F(x)=log(smallb)x is the set of all positive real numbers.
OpenStudy (anonymous):
sorry hold on
ganeshie8 (ganeshie8):
lets analyze the case 0< a < 1
OpenStudy (anonymous):
for this problem wouldn't it be all real numbers not just positive real numbers??
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ganeshie8 (ganeshie8):
yes, so its false
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
then this:
what is the domain?
F(x)= 2+log(small 0.6)x
OpenStudy (anonymous):
it would be x>0 correct?
ganeshie8 (ganeshie8):
no translation in x side, oly a shrink in hte graph
so, domain wont change from the regular x > 0
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OpenStudy (anonymous):
k
OpenStudy (anonymous):
then:
what is the x-intercept of F(x)=log(small 0.25)x
OpenStudy (anonymous):
I got 1, something
OpenStudy (anonymous):
I think. (1,0)/ or it could be 1, something else
ganeshie8 (ganeshie8):
x-intercept is a point on x
so it will be of form (k, 0)
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OpenStudy (anonymous):
ok so then (1,0
ganeshie8 (ganeshie8):
(1, 0) = \(\checkmark\)
OpenStudy (anonymous):
ok and then:
true or false.
The function F(x)= log(small3)x is decreasing
ganeshie8 (ganeshie8):
remember this :-
\(y = \log_b x\)
if b > 1, function is increasing
i b is between 0 and 1, function is decreasing
ganeshie8 (ganeshie8):
*if
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OpenStudy (anonymous):
so its increasing
wow idk why I just asked u that. its like @ the very bottom of my notes
ganeshie8 (ganeshie8):
good u have a notes :)
OpenStudy (anonymous):
yea
ganeshie8 (ganeshie8):
one thing about ur original FIRST question
ganeshie8 (ganeshie8):
true or false?
the domain of F(x)= log(small b)x is the set of all positive real numbers.
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ganeshie8 (ganeshie8):
thats ur first question, right ?
OpenStudy (anonymous):
yea why?
ganeshie8 (ganeshie8):
domain of log x is x > 0
so false
OpenStudy (anonymous):
I think u said that already
ganeshie8 (ganeshie8):
i had a typo there, i meant to type below :-
domain of log x is x > 0
so true
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OpenStudy (anonymous):
is the x- intercept of F(x)= log(small 2)x (1,0) ??
OpenStudy (anonymous):
wait r u serious????????????
OpenStudy (anonymous):
noooooo I missed that one!!!!!
ganeshie8 (ganeshie8):
yes ! x > 0 means, its all positive numbers. so its true
ganeshie8 (ganeshie8):
u doing flvs ?
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OpenStudy (anonymous):
:( :(
ganeshie8 (ganeshie8):
giving exam is it ?
OpenStudy (anonymous):
no, it was a mini 3 question quiz w/ notes but it was stage 2. where u can go back and change things :)
OpenStudy (anonymous):
so I missed it :(
ganeshie8 (ganeshie8):
ohk sorry about that
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OpenStudy (anonymous):
so is the answer to my latest question correct? :( :( ○○○○
OpenStudy (anonymous):
it's ok..
ganeshie8 (ganeshie8):
correct
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
oh great
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OpenStudy (anonymous):
Im entering this new unit..... and I think it's proofs :(
ganeshie8 (ganeshie8):
this is algebra or geometry ?
OpenStudy (anonymous):
algebra ii
OpenStudy (anonymous):
sorry I think I said proofs instead of "proof" the term
OpenStudy (anonymous):
:p
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ganeshie8 (ganeshie8):
okie :) good luck !!!
OpenStudy (anonymous):
thanks so much!!! :)
ganeshie8 (ganeshie8):
np :)