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Geometry 9 Online
OpenStudy (anonymous):

please help!!! If you divided the length of AQ by the length of WQ , what is the solution? 2 3 1/3 1/2 https://rialto5819-ehs-pps.gradpoint.com/Resource/2146263,72F,0,0,0,0,0/Assets/testitemimages/geometry_a/tools_of_geometry/mc082-1.jpg

OpenStudy (anonymous):

length oa AQ is 4 units and that of WQ is 12 units hence reqd ans =4/12=1/3

OpenStudy (anonymous):

how didi yoU get WQ, please explain

OpenStudy (anonymous):

did

OpenStudy (anonymous):

@matricked

jimthompson5910 (jim_thompson5910):

count how many spaces there are between W and Q you'll count 12 spaces or you can do it numerically by subtracting 4 - (-8) = 4 + 8 = 12

OpenStudy (anonymous):

ok thank you be cause i got -12 not 12

jimthompson5910 (jim_thompson5910):

distance is always positive

jimthompson5910 (jim_thompson5910):

so if you got a negative result from subtraction, you make the result positive

jimthompson5910 (jim_thompson5910):

-8 - 4 = -12 make it positive to get 12

OpenStudy (anonymous):

thank you guys so much

jimthompson5910 (jim_thompson5910):

you're welcome

OpenStudy (anonymous):

@jim_thompson5910 can you want to help me with some other questions please?

jimthompson5910 (jim_thompson5910):

sure

jimthompson5910 (jim_thompson5910):

just a few though

OpenStudy (anonymous):

ok :)

OpenStudy (anonymous):

M(5, 7) is the midpoint of RS . The coordinates of S are (6, 9). What are the coordinates of R? (7, 11) (10, 14) (5.5, 8) (4, 5)

jimthompson5910 (jim_thompson5910):

let's make R the point (x,y) for now

jimthompson5910 (jim_thompson5910):

M is the midpoint, so if you average the corresponding coordinates of R and S, you'll get the coordinates of M

jimthompson5910 (jim_thompson5910):

this means you will have these 2 equations (x+6)/2 = 5 and (y+9)/2 = 7

OpenStudy (anonymous):

I GOT 4 AND 5

OpenStudy (anonymous):

The Frostburg-Truth bus travels on a straight road from Frostburg Mall to Sojourner Truth Park. The mall is 5 miles west and 3 miles south of the City Center. The park is 4 miles east and 4 miles north of the Center. How far is it from the mall to the park to the nearest tenth of a mile? 5.7 miles 5.8 miles 1.4 miles 11.4 miles

jimthompson5910 (jim_thompson5910):

(x,y) = (4,5) very good

OpenStudy (anonymous):

The Frostburg-Truth bus travels on a straight road from Frostburg Mall to Sojourner Truth Park. The mall is 5 miles west and 3 miles south of the City Center. The park is 4 miles east and 4 miles north of the Center. How far is it from the mall to the park to the nearest tenth of a mile? 5.7 miles 5.8 miles 1.4 miles 11.4 miles

jimthompson5910 (jim_thompson5910):

one sec

OpenStudy (anonymous):

alright

jimthompson5910 (jim_thompson5910):

the best way to do this is to set up a coordinate system where the city center is at (0,0) then you go 5 units to the left, then 3 units down to land at (-5, -3)...this is the mall now go back to (0,0) and go to the right 4 and go up 4 units to get (4,4)...this is the park

jimthompson5910 (jim_thompson5910):

your job is to find the distance between the two points (-5, -3) and (4,4)

OpenStudy (anonymous):

ohh the distance formula right

jimthompson5910 (jim_thompson5910):

correct

OpenStudy (anonymous):

i got -16

OpenStudy (anonymous):

i mean 4

jimthompson5910 (jim_thompson5910):

hmm not sure how you got that

jimthompson5910 (jim_thompson5910):

you used this formula right d = sqrt((x2-x1)^2+(y2-y1)^2) ?

OpenStudy (anonymous):

yes but since i got it wrong can you show me

jimthompson5910 (jim_thompson5910):

sure

jimthompson5910 (jim_thompson5910):

d = sqrt((x2-x1)^2+(y2-y1)^2) d = sqrt((4-(-5))^2+(4-( -3))^2) d = sqrt((4+5)^2+(4-( -3))^2) d = sqrt((9)^2+(7)^2) d = sqrt(81+49) d = sqrt(130) So exact distance between the two points is sqrt(130) units. Using a calculator, the approximate distance is roughly 11.40175 units.

OpenStudy (anonymous):

thank you

jimthompson5910 (jim_thompson5910):

sure thing

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