please help!!! If you divided the length of AQ by the length of WQ , what is the solution? 2 3 1/3 1/2 https://rialto5819-ehs-pps.gradpoint.com/Resource/2146263,72F,0,0,0,0,0/Assets/testitemimages/geometry_a/tools_of_geometry/mc082-1.jpg
length oa AQ is 4 units and that of WQ is 12 units hence reqd ans =4/12=1/3
how didi yoU get WQ, please explain
did
@matricked
count how many spaces there are between W and Q you'll count 12 spaces or you can do it numerically by subtracting 4 - (-8) = 4 + 8 = 12
ok thank you be cause i got -12 not 12
distance is always positive
so if you got a negative result from subtraction, you make the result positive
-8 - 4 = -12 make it positive to get 12
thank you guys so much
you're welcome
@jim_thompson5910 can you want to help me with some other questions please?
sure
just a few though
ok :)
M(5, 7) is the midpoint of RS . The coordinates of S are (6, 9). What are the coordinates of R? (7, 11) (10, 14) (5.5, 8) (4, 5)
let's make R the point (x,y) for now
M is the midpoint, so if you average the corresponding coordinates of R and S, you'll get the coordinates of M
this means you will have these 2 equations (x+6)/2 = 5 and (y+9)/2 = 7
I GOT 4 AND 5
The Frostburg-Truth bus travels on a straight road from Frostburg Mall to Sojourner Truth Park. The mall is 5 miles west and 3 miles south of the City Center. The park is 4 miles east and 4 miles north of the Center. How far is it from the mall to the park to the nearest tenth of a mile? 5.7 miles 5.8 miles 1.4 miles 11.4 miles
(x,y) = (4,5) very good
The Frostburg-Truth bus travels on a straight road from Frostburg Mall to Sojourner Truth Park. The mall is 5 miles west and 3 miles south of the City Center. The park is 4 miles east and 4 miles north of the Center. How far is it from the mall to the park to the nearest tenth of a mile? 5.7 miles 5.8 miles 1.4 miles 11.4 miles
one sec
alright
the best way to do this is to set up a coordinate system where the city center is at (0,0) then you go 5 units to the left, then 3 units down to land at (-5, -3)...this is the mall now go back to (0,0) and go to the right 4 and go up 4 units to get (4,4)...this is the park
your job is to find the distance between the two points (-5, -3) and (4,4)
ohh the distance formula right
correct
i got -16
i mean 4
hmm not sure how you got that
you used this formula right d = sqrt((x2-x1)^2+(y2-y1)^2) ?
yes but since i got it wrong can you show me
sure
d = sqrt((x2-x1)^2+(y2-y1)^2) d = sqrt((4-(-5))^2+(4-( -3))^2) d = sqrt((4+5)^2+(4-( -3))^2) d = sqrt((9)^2+(7)^2) d = sqrt(81+49) d = sqrt(130) So exact distance between the two points is sqrt(130) units. Using a calculator, the approximate distance is roughly 11.40175 units.
thank you
sure thing
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