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OpenStudy (explainitlikeimfive):
\[y = \sin (\theta-2) \]
OpenStudy (explainitlikeimfive):
OpenStudy (explainitlikeimfive):
OpenStudy (anonymous):
y=sin(x-a)
A shift of the sine graph a units to the right
OpenStudy (anonymous):
y=sin(x+a)
A shift of the sine graph a units to the left
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OpenStudy (anonymous):
y=sin(x)+a
A shift of the sine grpah a units up
y=sin(x)-a
A shift of the sine graph a units down
OpenStudy (explainitlikeimfive):
From what I understand, I would pick C.
ganeshie8 (ganeshie8):
y=sin(x-2)
shifts right by 2 units
ganeshie8 (ganeshie8):
strike off A and C
cuz they have graphs shifted UP/DOWN
ganeshie8 (ganeshie8):
your answer is either B or D
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OpenStudy (explainitlikeimfive):
I choose B.
ganeshie8 (ganeshie8):
thats correct ! but why, do u have a reason ? :)
OpenStudy (explainitlikeimfive):
Process of Elimination
ganeshie8 (ganeshie8):
why did u eliminate D
OpenStudy (anonymous):
Yep, these graphs look funny, the best way to determine it is to just plug in something like pi and see where it lands you on the grpah which is like sin(pi-2)=.9093 APPROX SO FIND ONE WHERE IT WAS
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OpenStudy (explainitlikeimfive):
I answered D orginally, and it was wrong.
ganeshie8 (ganeshie8):
lol that surely is a good reason :)
OpenStudy (explainitlikeimfive):
Thanks to all.
OpenStudy (anonymous):
sorry my caps come on anmd off lol
OpenStudy (explainitlikeimfive):
I was wondering why you were yelling
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ganeshie8 (ganeshie8):
as doulikepie says, just put \(\theta = 0\),
then \(\sin (0 -2) = \sin (-2) \) = negative number
since D has positive when \(\theta = 0\), we eliminate D
OpenStudy (explainitlikeimfive):
First come first served on medals. @doulikepiecauseidont