Determine the number of solutions for the quadratic function f(x) = -x2 + 3x - 9?
I said there is none
If by solution you mean roots, then there are 2 imaginary roots.
how is there 2 distinct real solutions...?
just check the discriminant value (D), with D = b^2 - 4ac if D > 0 then there are 2 distinc real solutions if D = 0 then there is one real solution (the roots are same) if D < 0 then there are 2 imaginary solutions (the roots not real)
So it is 2 distinct real solutions! Thanks guys!
no
i didnt say that --"
1 solution with a double root?
if D < 0 then there are 2 imaginary solutions (the roots not real)
f(x) = -x2 + 3x - 9 according information above, a = -1, b = 3, c = -9 D = b^2 - 4ac D = 3^2 - 4(-1)(-9) D = 9 - 36 D = -27 that means D < 0 take your conclution, now
I'm confused as pellet right now. No real solutions or 1 solution (double root) or 2 distinct real solutions or 3 solutions
Those are all my guesses :\
No real solution.
no solution is your case
I was right in the first place. What the...
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