Mathematics
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OpenStudy (anonymous):
what is equivalent to the expression below. select all that apply.
3^4*3^x
A. 3^(4-x)
B. 81*(3^x)
C. (3*x)^4
D. 3^(4x)
E. 3^(4+x)
F. 9^(4x)
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OpenStudy (blurbendy):
actually
OpenStudy (blurbendy):
since the base of the exponents are the same, do you remember what you can do with that fact?
OpenStudy (anonymous):
81
OpenStudy (anonymous):
so B is an answer
OpenStudy (anonymous):
then.... what else
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OpenStudy (blurbendy):
if you have two bases that are the same:
a^2 + a^2,
then you can add the exponents to get:
a^(2+2)
OpenStudy (blurbendy):
so B is an answer and so is E
OpenStudy (anonymous):
oops I forgot-sorry it was on the very bottom of my notes
OpenStudy (anonymous):
so yes E is also an answer
OpenStudy (anonymous):
is that it though?
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OpenStudy (blurbendy):
yes, none of the other ones work
OpenStudy (anonymous):
omg! did really bad on a few of thse questions so can u help me w/ like a few more questions pls??
OpenStudy (blurbendy):
ok
OpenStudy (anonymous):
ok i'll post it now
OpenStudy (anonymous):
which are equivalent below,. select all that apply.
9^x
A. 9*(9^(x-1))
B. (36/4)^x
C. 9*(9^(x+1))
D. (36^x)/4
E. 36^x/4^x
F. x^5
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OpenStudy (anonymous):
ok so I know that B & E will work
OpenStudy (anonymous):
but im not sure abt the others
OpenStudy (blurbendy):
A works as well
OpenStudy (anonymous):
ok so A, B & E ?
OpenStudy (anonymous):
but how is A though?
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OpenStudy (blurbendy):
9 * 9^(x - 1) = 9 * 1/9 * 9^x
OpenStudy (blurbendy):
9 and 1/9 cancel out to equal 1, and 1 * 9^x = 9^x
OpenStudy (blurbendy):
9^(-1) = 1/9
OpenStudy (anonymous):
ok the next one is the same type of problem w/ same intructions
OpenStudy (blurbendy):
ok
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OpenStudy (anonymous):
question: 2^5*2^x
A. 2^(5x)
B. 4^(5x)
C. 2^(5-x)
D. (2*x)^5
E. 2^(5+x)
F. 32*(2^x)
OpenStudy (blurbendy):
2^5 is 32 so F will work.
2^(5+x) will also work (same bases mead we can add the exponents.
none of the others work
OpenStudy (anonymous):
yeah I had F
OpenStudy (anonymous):
wait E also works too
OpenStudy (anonymous):
so E & F
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OpenStudy (blurbendy):
yes
OpenStudy (anonymous):
next question: 16^x
A. 4*(4^x)
B. 4*(4^2x)
C. 4^2*4^x
D. 4^(2x)
E. 4^x*4^x
F. (4*4)^x
OpenStudy (anonymous):
I know E & F works
OpenStudy (anonymous):
is that it? that's all I could find
OpenStudy (blurbendy):
d works
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OpenStudy (anonymous):
4^(2x)?? how?
OpenStudy (blurbendy):
4^(2x) = 4^2*4^x which is the same as E
OpenStudy (blurbendy):
wait no it's not
OpenStudy (anonymous):
yea.... cuz then they'd have to add together not multiply
OpenStudy (blurbendy):
wait
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OpenStudy (anonymous):
ok
OpenStudy (blurbendy):
it might be a good idea to get a second opinion because im not sure actually
OpenStudy (anonymous):
ok..
OpenStudy (blurbendy):
just post the question
OpenStudy (anonymous):
i'm gonna close this question and put the one we were discussing
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OpenStudy (blurbendy):
kk