Question

Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3).

Answer 1

what is the slope of -> y = 2x + 2 ?

Answer 2

jdoe it should be 2 wouldnt you think. I mean i had trouble with this to but i think the slope of it is 2

Answer 3

yes, it's

Answer 4

y = 2x + 6

y = −one halfx + 3

y = −one halfx + 6

y = 2x + 3

these are the choices

Answer 5

well, perpendicular lines have NEGATIVE RECIPROCAL slopes
what does that mean?

since this one has 2
the RECIPROCAL of that is
1/2

the NEGATIVE of that is
-1/2

Answer 6

ok so what would the answer be?

Answer 7

so, now you have, the slope of -1/2 of the line that passes through (6, 3)
using the point-slope form, of => \(\huge \bf y-y_1=m(x-x_1)\)
m = slope
(6, 3) = \(\bf \large x_1, y_1\)
use that and your values, and solve for "y" to get your equation :)

Answer 8

ok so would the answer be y = −one halfx + 6

Answer 9

yes

Answer 10

thank you

Answer 11

yw

Answer 12

I have another question for you if you dont mind

Answer 13

ok