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Write the equation of the line that is parallel to the line y = −3x + 12 and passes through the point (−1, 6).
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y = one thirdx + 7 y = −3x + 3 y = one thirdx + 3 y = −3x + 7 these are the choices
same as the one before, just that, parallel lines have EXACTLY the same slope, so the slope of => y = −3x + 12 is -3 so any parallel line to it will also have a slope of -3 so => \(\bf \large y-y_1=m(x-x_1)\) m = slope (-1, 6) = \(\bf \large (x_1, y_1)\)
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