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f(x) = x + 5 g(x) = x2 -4x + 5 h(x) = 3x2 - 2x + 5 h[f(5)] - g[h(1)]
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Just plug in.
@Jhannybean
ummmmm
first find f(5).\[\large f(5) = (5) +5 = \ ?\]
10
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Then \[g(x) = x^2 -4x+5\]\[h(x) = 3x^2-2x+5\]Find h(1).\[h(1) = 3(1)^2 -2(1)+5 = \ ?\]
What do you get @jazzyfa30 ?
h=2????
3-2+5..= ? ...
oh 6
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Yep. so.. if g(x) = x^2-4x+5, then g(h(1)) = g(6) = (6)^2 -4(6)+5 =...?
17???
I've got to head out in a few minutes :(
ok this is my last Q anyway
Yes, 17.
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so we've got h(10-17)
that means we're solving for h(-7)
h(-7) = 3(-7)^2 - 2(-7) + 5 = ?
432????
147 +14 + 5 =?
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ohh 166
yes good job.
so the answer is 166
Yes :)
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