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Mathematics 13 Online
OpenStudy (anonymous):

Find the product. (3p – 7)(3p + 7) a. 9p^2 – 49 b. 9p^2 + 42p + 49 c. 9p^2 + 49 d. 9p^2 – 42^p – 49

OpenStudy (anonymous):

Use \( a^2 - b^2 \) where (a - b)(a + b)

OpenStudy (anonymous):

Do you understand?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

\( a^2 \) = 3p time 3p = \( 9p^2 \) can you solve for \( b^2 \) which is \(-7^2\)

OpenStudy (anonymous):

......

OpenStudy (anonymous):

Do you know how to do exponents ?

OpenStudy (anonymous):

What is \(2^2 \)

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

4

OpenStudy (anonymous):

Ok, what is \( -7^2 \) ?

OpenStudy (anonymous):

49

OpenStudy (anonymous):

Yes, so \( 9p^2 + 49 \) is the answer

OpenStudy (anonymous):

We just used the formula known as a^2 + b^2 It is a fast way of doing these types of problems when you have the same numbers in the factors, which is (3p - 7) (3p + 7) and when you have different signs, which we have a + and a -

OpenStudy (anonymous):

You could of used the FOIL method but it is a lot longer.

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