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Find the product. (3p – 7)(3p + 7) a. 9p^2 – 49 b. 9p^2 + 42p + 49 c. 9p^2 + 49 d. 9p^2 – 42^p – 49
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Use \( a^2 - b^2 \) where (a - b)(a + b)
Do you understand?
no
\( a^2 \) = 3p time 3p = \( 9p^2 \) can you solve for \( b^2 \) which is \(-7^2\)
......
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Do you know how to do exponents ?
What is \(2^2 \)
yea
4
Ok, what is \( -7^2 \) ?
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49
Yes, so \( 9p^2 + 49 \) is the answer
We just used the formula known as a^2 + b^2 It is a fast way of doing these types of problems when you have the same numbers in the factors, which is (3p - 7) (3p + 7) and when you have different signs, which we have a + and a -
You could of used the FOIL method but it is a lot longer.
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