Question

What is the perimeter of a square that has a side of \sqrt{72} ? Write your answer in simplest radical form.

Answer 1

perimeter of a square is x+x+x+x = 4x where x is the length of the side

Answer 2

i dont think there is a square root of 72

Answer 3

there is

Answer 4

sure there is. its just not "Nice"

Answer 5

you can take the square root of any non negative real number

Answer 6

\[24\sqrt{4}\]

Answer 7

The perimeter, P, of a square is 4 times the side, s.
\(P = 4s\)
\(P = 4 \times \sqrt{72} \)
Now you need to simplify.

Answer 8

sqrt(4) = 2

Answer 9

um sqrt(72) = sqrt(36*2) = sqrt(36)*sqrt(2) = 6swrt(2)

Answer 10

square root of any prime is irrational, thus we just leave it alone. because there is NO other way to write it.

Answer 11

uhh dont u have to do something to make it 4 yimrd

Answer 12

yimrd?

Answer 13

times i meant to write times

Answer 14

Im so confused.

Answer 15

\(P = 4 \times \sqrt{72} = 4 \times \sqrt{36 \times 2} =4 \times 6 \sqrt{2}
= 24 \sqrt{2} \)

Answer 16

you have a square with side sqrt(72), so the perimeter is 4*sqrt(72)
sqrt(72) is just a number.....
if your side was 10 then it would be 10*4

Answer 17

so what would be the answer

Answer 18

the answer would be \[24\sqrt{2}\]

Answer 19

correct

Answer 20

4*6*sqrt(2) = 4*sqrt(72)