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Mathematics 24 Online
OpenStudy (anonymous):

x+1=9x^3 + 9x^2

OpenStudy (rsadhvika):

factor the gcf right side

OpenStudy (anonymous):

9x^3+9X^2-x-1+0 9x^2(x+1) -1(x+1) 9x^2-1=0 x+1=0

OpenStudy (anonymous):

yes or no?

OpenStudy (rsadhvika):

yes

OpenStudy (anonymous):

45x^-x-1

OpenStudy (anonymous):

now solve it

OpenStudy (anonymous):

thank u ranthanreddy, i have help already

OpenStudy (anonymous):

9x^3+9X^2-x-1+0 9x^2(x+1) -1(x+1) 9x^2-1=0 x+1=0

OpenStudy (anonymous):

on the right its going be x=-1

OpenStudy (anonymous):

lost on left side!

OpenStudy (rsadhvika):

9x^3+9X^2-x-1 = 0 9x^2(x+1) -1(x+1) = 0 9x^2-1=0 x+1=0 9x^2 =1, x = -1 x^2 = 1/9, x = -1 x = 1/3, -1/3, x = -1 overall, x = {1/3, -1/3, -1}

OpenStudy (anonymous):

since we did the sq rt thats how u get a pos and neg?

OpenStudy (rsadhvika):

yes

OpenStudy (rsadhvika):

x^2 = 1/9 x = \(\pm \sqrt{1/9}\)

OpenStudy (anonymous):

i b lost in math, how am i supposed to know when a problem has 1 or 2 or 3 different answers?

OpenStudy (raden):

9x^2-1=0 (3x + 1)(3x - 1) = 0 set each factor be zero then solve for x

OpenStudy (rsadhvika):

here, highest power is 3, so you will have 3 answers MOST of the time

OpenStudy (rsadhvika):

you will NEVER have more than 3 answers - thats for sure

OpenStudy (anonymous):

but in quadratic 2x^3+3x^2+5x+5=0 has only 2 answers

OpenStudy (rsadhvika):

its a cubic, it will have 3 answers

OpenStudy (anonymous):

true or false?

OpenStudy (rsadhvika):

quadratic means, highest power is 2

OpenStudy (anonymous):

so 2x^2+3x-4=0 has only 2 answers?

OpenStudy (rsadhvika):

it can have 2 or 1 answer

OpenStudy (rsadhvika):

only thing we can say for sure is :- it cannot have more than 2 answers

OpenStudy (anonymous):

the ones that has 3 does it mean they can have up to three or always has three?

OpenStudy (rsadhvika):

exactly, they can have upto three answers

OpenStudy (rsadhvika):

cubic equations can have upto 3 answers quadratic equations can have upto 2 answers

OpenStudy (anonymous):

so, i have to go back and plug in the answers in the original equation to see if they work?

OpenStudy (rsadhvika):

not needed

OpenStudy (anonymous):

and if they dont, throw away and not include in ultimate answer?

OpenStudy (rsadhvika):

once you solve, you will end up with 3 or 2 or 1 answers. they will be the answers.

OpenStudy (anonymous):

what not needed?

OpenStudy (rsadhvika):

not needed to plug them back and check

OpenStudy (anonymous):

oh, i see....but i seen professor plugging back in the equation, i coulda swore a number didnt work and he didnt include in answer

OpenStudy (rsadhvika):

for the first problem we got 3 answers :- x = {1/3, -1/3, -1} they're the answers, we dont need to plug them back in equation and check if they satisfy or not.

OpenStudy (anonymous):

im new to site, how can i give you merit?

OpenStudy (rsadhvika):

here is the thing :- plugging back is NOT necessary for quadratic/cubic equations plugging back is necessary for radical equations

OpenStudy (anonymous):

you have been very resourceful this morning, my night....thank you so much...wish i could have you as tutor

OpenStudy (rsadhvika):

cuz, radical equations give you extraneous solutions, so you must always verify the answers u got by plugging them in the given equation, and throw away those that dont satisfy

OpenStudy (rsadhvika):

for quadratic/cubic, we never plug them back. cuz there wont be any extraneous solutions.

OpenStudy (anonymous):

radical equation has sq rt in original problem ?

OpenStudy (rsadhvika):

yes !

OpenStudy (anonymous):

how can i give you merit for your help?

OpenStudy (rsadhvika):

when u h ave sqrt, and u square... then u wil endup with extraneous solutions, you need to check domain continuously at each step

OpenStudy (rsadhvika):

np :) im fine

OpenStudy (anonymous):

u sure. i see u only asked 9 questions but answered almost 300

OpenStudy (rsadhvika):

lol i have another account where i ask all crazy questions i get

OpenStudy (anonymous):

thats silly!

OpenStudy (rsadhvika):

:)

OpenStudy (anonymous):

well, wishful thinking says "i wish i could contact you for more help"

OpenStudy (anonymous):

thanx a million see ya

OpenStudy (rsadhvika):

sure just holler when you feel stuck :) cya

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