x+1=9x^3 + 9x^2
factor the gcf right side
9x^3+9X^2-x-1+0 9x^2(x+1) -1(x+1) 9x^2-1=0 x+1=0
yes or no?
yes
45x^-x-1
now solve it
thank u ranthanreddy, i have help already
9x^3+9X^2-x-1+0 9x^2(x+1) -1(x+1) 9x^2-1=0 x+1=0
on the right its going be x=-1
lost on left side!
9x^3+9X^2-x-1 = 0 9x^2(x+1) -1(x+1) = 0 9x^2-1=0 x+1=0 9x^2 =1, x = -1 x^2 = 1/9, x = -1 x = 1/3, -1/3, x = -1 overall, x = {1/3, -1/3, -1}
since we did the sq rt thats how u get a pos and neg?
yes
x^2 = 1/9 x = \(\pm \sqrt{1/9}\)
i b lost in math, how am i supposed to know when a problem has 1 or 2 or 3 different answers?
9x^2-1=0 (3x + 1)(3x - 1) = 0 set each factor be zero then solve for x
here, highest power is 3, so you will have 3 answers MOST of the time
you will NEVER have more than 3 answers - thats for sure
but in quadratic 2x^3+3x^2+5x+5=0 has only 2 answers
its a cubic, it will have 3 answers
true or false?
quadratic means, highest power is 2
so 2x^2+3x-4=0 has only 2 answers?
it can have 2 or 1 answer
only thing we can say for sure is :- it cannot have more than 2 answers
the ones that has 3 does it mean they can have up to three or always has three?
exactly, they can have upto three answers
cubic equations can have upto 3 answers quadratic equations can have upto 2 answers
so, i have to go back and plug in the answers in the original equation to see if they work?
not needed
and if they dont, throw away and not include in ultimate answer?
once you solve, you will end up with 3 or 2 or 1 answers. they will be the answers.
what not needed?
not needed to plug them back and check
oh, i see....but i seen professor plugging back in the equation, i coulda swore a number didnt work and he didnt include in answer
for the first problem we got 3 answers :- x = {1/3, -1/3, -1} they're the answers, we dont need to plug them back in equation and check if they satisfy or not.
im new to site, how can i give you merit?
here is the thing :- plugging back is NOT necessary for quadratic/cubic equations plugging back is necessary for radical equations
you have been very resourceful this morning, my night....thank you so much...wish i could have you as tutor
cuz, radical equations give you extraneous solutions, so you must always verify the answers u got by plugging them in the given equation, and throw away those that dont satisfy
for quadratic/cubic, we never plug them back. cuz there wont be any extraneous solutions.
radical equation has sq rt in original problem ?
yes !
how can i give you merit for your help?
when u h ave sqrt, and u square... then u wil endup with extraneous solutions, you need to check domain continuously at each step
np :) im fine
u sure. i see u only asked 9 questions but answered almost 300
lol i have another account where i ask all crazy questions i get
thats silly!
:)
well, wishful thinking says "i wish i could contact you for more help"
thanx a million see ya
sure just holler when you feel stuck :) cya
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