hich inequality matches the graph below? y > |x + 2| + 1 y < |x – 2| + 1 y > |x + 2| – 1 y < |x – 2| – 1
I think its y > |x + 2| + 1 but im not sure
Could you explain how you got it? (Partly because I have no idea how to get this except through messy logic :P )
since its y> its going to be shaded upwards and the point is at (2,1) lol so it cant be the -1
Here's my logic... \[\Large y -\color{blue}b= |x-\color{red}a|\] Is going to be a right-angle \(\Large\lor\) shape where the vertex is on the point \(\large(\color{red}a,\color{blue}b)\) Right?
yes
Well, then, its center is (2,1) So a = 2, and b =1 So we have... \[\Large y -\color{blue}1 = |x-\color{red}2|\] or equivalently \[\Large y = |x-\color{red}2|+\color{blue}1\]
So it really is either the first or second, right?
Yea
I have to go now, but here's the last hint... hopefully, the last one you'll need... the point (0,0) is in the shaded part, but it will only satisfy one of the first two inequalities... which is it? :) Think about it... ------------------------------------ Terence out
I still believe its the first one because its shaded upwards im not sure tho
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