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If you add the digits in a two-digit number and multiply the sum by 7, you get the original number. If you reverse the digits in the two-digit number, the new number is 18 more than the sum of its two digits. What is the original number? A. 42 B. 24 C. 64 D. 46 E. 36
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(a + b) * 7 = ab ba = 18 + (a + b) I will just use process of elimination... (A) 42......(4 + 2) * 7 = 42 24 = 18 + (2 + 4) 24 = 18 + 6 24 = 24 (CORRECT) (B) 24......(2 + 4) * 7 = 42 : NOT CORRECT (C) 64 ....(6 + 4) * 7 = 70 : NOT CORRECT (D) 46 ....(4 + 6) * 7 = 70 : NOT CORRECT (E) 36 ....(3 + 6) * 9 = 81 : NOT CORRECT ANSWER : A
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