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Differential Equations 14 Online
OpenStudy (anonymous):

Draw solution curves by drawing isoclines of the following equations. dy/dx = y, dy/dx = x^2 + y^2

OpenStudy (amistre64):

is that the same thing as drawing a vector field?

OpenStudy (anonymous):

yes

OpenStudy (amistre64):

seems tedious ...

OpenStudy (amistre64):

the slope at any given x value is equal to y ... the other one is just as simple ... the slope at 0,0 = 0; the slope at (5,2) = 29; etc ...

OpenStudy (anonymous):

in this equation x and y must assume? in order to find the value of c?

OpenStudy (amistre64):

x and y values are derived from a given point in the xy plane

OpenStudy (amistre64):

the slope is just defined at that point as: x^2 + y^2

OpenStudy (anonymous):

ok.thanks for your help

OpenStudy (amistre64):

y' = y ... at any given point (x,y), the slope is equal to y y' = x^2 + y^2 ... at any given point (x,y), the slope is equal to, well, x^2 + y^2 :)

OpenStudy (anonymous):

its origin is 0,0 .right?

OpenStudy (amistre64):

the origin is (0,0) yes

OpenStudy (anonymous):

okay. thank you very much :)

OpenStudy (amistre64):

when picking a solution curve, if we have an initial value, we start with the initial value :)

OpenStudy (amistre64):

good luck

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