Draw solution curves by drawing isoclines of the following equations. dy/dx = y, dy/dx = x^2 + y^2
is that the same thing as drawing a vector field?
yes
seems tedious ...
the slope at any given x value is equal to y ... the other one is just as simple ... the slope at 0,0 = 0; the slope at (5,2) = 29; etc ...
in this equation x and y must assume? in order to find the value of c?
x and y values are derived from a given point in the xy plane
the slope is just defined at that point as: x^2 + y^2
ok.thanks for your help
y' = y ... at any given point (x,y), the slope is equal to y y' = x^2 + y^2 ... at any given point (x,y), the slope is equal to, well, x^2 + y^2 :)
its origin is 0,0 .right?
the origin is (0,0) yes
okay. thank you very much :)
when picking a solution curve, if we have an initial value, we start with the initial value :)
good luck
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