Find the geometric mean of the pair of numbers: 81 and 4. Question 18 options: a) 38 b) 23 c) 28 d) 18
take the square root of the product ...
the geoMean of a and b is: sqrt(ab)
@amistre64 is right you just need to take the square root and then poof you get the answer
Ok if you really want the answer, look at other questions with different examples to figure it out.
amistre told you how to do it. find the square root of the product ( product means multiply the two numbers)
i dont know how to do that
can you multiply 81 and 4 ?
ive asked what the two numbers are but they wont tell me are the 81 and 4?
oh it is
81 x 4 is 324
yes, the sentence Find the geometric mean of the pair of numbers: 81 and 4. means use 81 and 4 now find the square root of 324 you should learn an important idea: factor the number into prime factors, and look for pairs of numbers. it is easiest if you start with 4*81 (don't multiply it out to get 324) instead, factor 4 into 2*2 and 81 into 3*3*3*3 so you have sqrt(2*2*3*3*3*3) pull out pairs of numbers
ok
sqrt(2*2*3*3*3*3) = sqrt(2*2) * sqrt(3*3) * sqrt(3*3) and sqrt(2*2)= 2 sqrt(3*3)= 3 sqrt(3*3)= 3
im still lost a little
do you agree 324 = 2*2*3*3*3*3 ?
yes
do you know that sqrt( A * A) = A you can simplify two A's inside a square root by making them 1 A outside the square root
that rule works for sqrt(2*2*3*3*3*3) notice you can write that as sqrt( (2*3*3) * (2*3*3) ) by writing the numbers as pairs you can simplify that to sqrt( (2*3*3) * (2*3*3) ) = 2*3*3
or you can say: for every pair inside the square root, I can take that pair out, and put one of the pair outside the square root so : sqrt(2*2*3*3*3*3) = 2 sqrt(3*3*3*3) we took out the 2*2 from inside, and put a single 2 on the outside we can to that for the 3's also: 2 * 3* sqrt(3*3) we took out 1 pair of 3's we can take out the last pair of 3's 2*3*3*sqrt(1) = 2*3*3= 18
ok
or use a calculator on sqrt(324) (but it would be good to be able to do it without a calculator)
the sqrt is 18
yes, that means the geometric mean of 4 and 81 is 18
ok Thanks :DD
i have 5 more questions can you help me with those also?
Join our real-time social learning platform and learn together with your friends!