Question

Solve: 6x - 2 > 8x + 4

x > -3

x greater than or equal to -3

x < -3

x less than or greater to -3

Answer 1

@Babyjaguar<3

Answer 2

First, you need all x's on the left side and all numbers on the right side.
To start, subtract 8x from both sides.
Can you do that?

Answer 3

Ok

Answer 4

Now let's move all numbers to the right side.
Add 2 to both sides.

Answer 5

What do you have now?

Answer 6

I got x > -3

Answer 7

Wait. One step at a time. Let's go back to what I asked you to do.

6x - 2 > 8x + 4
-8x -8x
-------------------
-2x - 2 > 4
+2 +2
-----------------
-2x > 6

You did it up to this point and got what I got, -2x > 6 ?

Answer 8

Since you're not answering, I'll just continue, so you can reference the problem leter.

@goformit100 Please look at this.

Now comes the last step.
Since x is being multiplied by -2, you need to divide both sides by -2.
In an equation, you just do it, but in an inequality, there is a little extra step you need to do.

When you multiply both sides of an equation or divide both sides of an equation by a NEGATIVE NUMBER, the inequality sign changes direction.

\(-2x > 6 \)

\(\dfrac{-2x}{-2} < \dfrac{6}{-2} \)

\(x < -3\)

Answer 9

ok