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Help meeeeeeeeeeeee. Which of the following is the solution to the equation square root of 5^8n = 125^(n + 3) ?
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write 125 as 5^3
okay..then what?
then you will see bases are equal, so exponents also will be equal set them equal and solve n
can you solve me thrugh it? i get confused on this section real easy..
\(\large \sqrt{5^{8n} } = 125^{(n+3)} \)
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\(\large 5^{8n\times \frac{1}{2}} = 5^{3(n+3)} \) \(\large 5^{4n} = 5^{3(n+3)} \)
since bases are equal, you can set the exponents equal
\(4n = 3(n+3) \)
you can solve n now ?
dude, thats way too long. here is a simpler way 5^8n =125^ n+3 5^8n =5^3(n+3) 8n=3n+9 5n=9 n= 9 / 5
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