solve the system of equations by elimination 3x+6y=5
-3x-3y=7
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jimthompson5910 (jim_thompson5910):
notice you have +3x in equation 1 and -3x in equation 2
jimthompson5910 (jim_thompson5910):
they add to
3x + (-3x) = 3x - 3x = 0x = 0
so effectively adding them gives you 0 (which goes away)
jimthompson5910 (jim_thompson5910):
this means that if you added both equations, you would get
3x+6y=5
-3x-3y=7
-----------
0x + 3y = 12
so we know that 3y = 12, which means y = ???
once you figure out y, you can solve for x
OpenStudy (anonymous):
thank you :)
jimthompson5910 (jim_thompson5910):
you're welcome
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OpenStudy (anonymous):
waiiiit I needed help solving x
OpenStudy (anonymous):
y=4
OpenStudy (anonymous):
but somehow I got 3x=-19 for x and it doesn't go
jimthompson5910 (jim_thompson5910):
good y = 4 is correct
jimthompson5910 (jim_thompson5910):
3x+6y=5
3x+6*4=5 ... plug in y = 4
3x + 24 = 5
3x = 5 - 24
3x = -19
x = -19/3
you can leave it as a fraction or convert to decimal form (it will be approximate though)
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jimthompson5910 (jim_thompson5910):
OR you can pick on the second equation
-3x-3y=7
-3x-3*4=7
-3x - 12 = 7
-3x = 7 + 12
-3x = 19
x = 19/(-3)
x = -19/3
either way, you'll get x = -19/3
OpenStudy (anonymous):
okay I thought I did something wrong
jimthompson5910 (jim_thompson5910):
nope you did it perfectly
jimthompson5910 (jim_thompson5910):
it's perfectly possible to get a fraction as an answer
OpenStudy (anonymous):
ahh okay then thanks again
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