How can you tell when a quadratic equation has no real solution?

Question

anonymous · Answer

Recall the quadratic equation

$$\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }$$

The discriminant which is the part $$\sqrt{b ^{2}- 4ac} <0$$

anonymous · Answer

I still dont understand it???

anonymous · Answer

lol :P

anonymous · Answer

if the discriminant is less than zero than you have no real solutions because you can't take the square root of negative numbers!!!

anonymous · Answer

you have to resort to complex numbers which are imaginary which means its not real!!

anonymous · Answer

oh lol okay
 thank you

anonymous · Answer

that makes why more sense now

anonymous · Answer

alright glad you understand now =)) good job.

anonymous · Answer

For which value of x does the graph of y = 3x2 − 2x − 5 cross the x-axis?

anonymous · Answer

factor it using the formula I gave you above!

anonymous · Answer

where a =3 b = -2 and c = -5 just remember! square roots have two solutions...

anonymous · Answer

i dont know any thing about math thats why im asking you Mebs..  please my Mebs for me lol

anonymous · Answer

you suck dude

anonymous · Answer

lol kk fine

anonymous · Answer

But really you have to try .... really O.o try

anonymous · Answer

so x = -1 and x = 5/3

anonymous · Answer

do I suck now ah.. huh huh common.. tell me lol?