solve the system of equations
5x-y=27
5x+4=42

Question

solve the system of equations
5x-y=27
5x+4=42

anonymous · Answer

Is there supposed to be a "y" in the second equation?

anonymous · Answer

ohh my bad its um 5x+4y=42

anonymous · Answer

Ok, what you can do is use the elimination method, since both equations have 5x, we can negate one of them. Lets negate the top equation and put it beneath the other one like this:
5x+4y=42
-5x+y=-27
---------- Now we can add these equations going down and it'll look like this:
5y=15
y=3

Now that you have y, you can plug it into either equation to solve for x.

anonymous · Answer

5x+4(3)=42
5x+12=42
    -12  -12
5x=30
x=6
(6,3)

anonymous · Answer

That looks good to be. You can check your answer by plugging the points into the original equations, or graphing them.

anonymous · Answer

okay thank you.

anonymous · Answer

You're welcome, glad I could help