Question

Please Help
Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1)
y=1/3x - 3
y=1/3x + 13
y = −3x − 3
y = −3x + 17

Answer 1

I think its s question of math

Answer 2

Yes

Answer 3

3x+y=7
y=-3x+7

Answer 4

you mean 17 instead of 7?

Answer 5

So slope of ur given line is m=-3

Answer 6

ok

Answer 7

ty

Answer 8

U know
m1*m2=-1
-3*m2=-1
m2=1/3

Answer 9

So the slope of ur required line is 1/3

Answer 10

So its going to be the first one?

Answer 11

Ya

Answer 12

ty

Answer 13

So the equation of ur required line will b
y-y1=m(x-x1)

Answer 14

Yes im sure of that

Answer 15

Here
m=1/3
x1=6
y1-1

Answer 16

So
y-(-1)=1/3(x-6)

Answer 17

Now finish it

Answer 18

the last one

Answer 19

No

Answer 20

y+1=1/3x-2
y=1/3x-3

Answer 21

Did u get it