Question

which of the following is equivalent to the expression (t^2-T-6)(T-3)^-1
a T^3-9t+18
b (T-2)(t+3)
c (T+2)(T-3)
d(T-2)
e (T+2)
Anwser is E but dont know how to get it

Answer 1

use your calculator and simplify all of them then c which has the same answer

Answer 2

i dont know how to type it on the calc

Answer 3

oh!

Answer 4

its E it gives u 2 same as the expression in the q'

Answer 5

oh whoops your right read the anwser sheet wrong

Answer 6

ok

Answer 7

do u have more q's?

Answer 8

ok gd luck with the rest :)

Answer 9

you have to know 2 things

first
\[(T-3)^{-1}= \frac{1}{(T-3)} \]

second, you need to be able to factor
\[ (T^2 -T -6) \]

to factor, first look at the last number: -6
write a pairs that give you 6 when you multiply:
1,6
2,3

the minus sign on the -6 means, look at the difference of each pair
1-6 = -5
2-3 = -1

if you find a difference that matches the middle number -T (which is -1 T)
use that pair:
2 and -3

write the factors (T+2)(T-3)

now you have
\[ \frac{(T+2)(T-3)}{(T-3)} = (T+2) \]
because (T-3) divided by (T-3) is 1