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Mathematics 14 Online
OpenStudy (anonymous):

The first ten letters of the alphabet are to be placed in a line, find the number of arrangements possible of A and B are together and the C,D, and F are not

OpenStudy (raden):

| A | B | | | | | | | | | first, find the number arrangements the event of A and B are together

OpenStudy (anonymous):

ok 18 then what?

OpenStudy (cwrw238):

the 3 letters C,D and F can then be arranged in the 8 places left in 8P3 ways that is the number of permutations of 3 letters in 8.

OpenStudy (cwrw238):

8P3 = 8! / (8 - 3)!

OpenStudy (cwrw238):

so possible arrangements = 18 * (8! / 5!)

OpenStudy (cwrw238):

are you familiar with 8! ( 8 factorial)

OpenStudy (cwrw238):

u still there?

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