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f(x) = Square root of quantity x plus nine.; g(x) = 8x - 13 Find f(g(x)). f(g(x)) = 2Square root of quantity two x minus one. f(g(x)) = 8Square root of quantity x minus four. f(g(x)) = 2Square root of quantity two x plus one. f(g(x)) = 8Square root of quantity x plus nine. - 13
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substitute 8x - 3 for the x in sqrt(+ 9) and simpify
okay i plugged in 8x-13 and i got \[\sqrt{8x-4}\]
can i reduce the 8x?
thanks
no - thats it
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