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Mathematics 9 Online
OpenStudy (anonymous):

Simplify 3x +9/3

OpenStudy (agent0smith):

\[\Large \frac{ 3x + 9 }{ 3 } = \frac{ 3x }{ 3} + \frac{ 9 }{ 3}\]

OpenStudy (agent0smith):

Try it that way, or this way, by taking the common factor of 3 out of the numerator: \[\Large \frac{ 3x + 9 }{ 3 } = \frac{ 3(x+3) }{ 3 }\]

OpenStudy (anonymous):

Thank you sooo much!

OpenStudy (anonymous):

What if the equation was all over 3x?

OpenStudy (agent0smith):

You're welcome. Then you're probably better using the second method: \[\Large \frac{ 3x + 9 }{ 3x } = \frac{ 3(x+3) }{ 3*x }\] I just put the star on the bottom to make it more obvious how to simplify. Can you see how to simplify it now?

OpenStudy (anonymous):

I think so!

OpenStudy (agent0smith):

You should get x+3 for your first question (where it's over 3), and (x+3)/x for your second question (over 3x).

OpenStudy (anonymous):

Yeah, that's what I ended up with!

OpenStudy (agent0smith):

Good :)

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