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Mathematics 66 Online
OpenStudy (anonymous):

Jimmy's Chocolate shop sells two different fudge bars. The dark chocolate fudge bar sells for $6.00 per pound and the milk chocolate fudge bar sells for $4.00 per pound. You purchased a combination of these bars for all of your family and friends for the holidays and your bill came to $120. This scenario can be modeled by the equation 6d + 4m = 120. Which of the following is not a possible combination of dark chocolate bars and milk chocolate bars?

OpenStudy (anonymous):

Which of the following???? i think u miss a part of the problem

OpenStudy (anonymous):

10 dark bars and 15 milk bars 12 dark bars and 12 milk bars 14 dark bars and 18 milk bars 6 dark bars and 21 milk bars this are the answer options

OpenStudy (anonymous):

u must replace each of these options for example for the option 1 u have 6*10 +4*15 =120 60 + 60=120 120=120 so the equation becomes true u must do the same with the other options and see when the equation becomes false

OpenStudy (anonymous):

ok thank you

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