Question

One number is 4 less than 3 times a second number. If 3 more than twice the first number is decreased by the second, the result is 11. Use the subsitution method. What Is The Number

Answer 1

Im So Confused lol

Answer 2

Here are The Choices
3
4
8
11

Answer 3

let x and y be the two numbers

Answer 4

Ok

Answer 5

One number is 4 less than 3 times a second number

means that

x = 3y - 4

Answer 6

ok Yes Im Following

Answer 7

oh wait, made a typo, one sec

Answer 8

3 more than twice the first number is decreased by the second, the result is 11

translates to

2x + 3 - y = 11


now you plug in x = 3y - 4 to get

2x + 3 - y = 11

2(3y - 4) + 3 - y = 11

6y - 8 + 3 - y = 11

5y - 3 = 11

...

y = ??? tell me what you get

Answer 9

3

Answer 10

oh sry, made another typo and it should be 5y - 5 = 11

but I'm not getting a whole number when I solve for y, one sec

Answer 11

maybe it's more like this

Answer 12

3 more than twice the first number is decreased by the second, the result is 11

translates to

2(x-y) + 3 = 11

Answer 13

Okay

Answer 14

if so, then

2(x-y) + 3 = 11

2(3y - 4-y) + 3 = 11

2(2y - 4) + 3 = 11

4y - 8 + 3 = 11

4y - 5 = 11

4y = 16

y = 4

x = 3y - 4

x = 3*4 - 4

x = 8


so it looks like the first number is 8

Answer 15

Okay Thanks

Answer 16

yw