Question

Find the point on the y-axis which is equidistant from A (-5, -2) and B (3, 2)

Answer 1

hint: if it is on the \(y\) axis it looks like \((0,y)\)

Answer 2

A's y-coordinate is -2
B's y-coordinate is 2

The midway point between -2 and 2 is 0.

Answer 3

hmmm i think maybe you need other work

Answer 4

the square of the distance between \((-5,-2)\) and \((0,y)\) is
\[5^2+(y+2)^2\]

Answer 5

Oh whoops. Didn't read the question fully. Ill let this fine person help you. I trust he can lead you to a correct answer. (I see what I did. Simple mistakes getcha)

Answer 6

and the square of the distance between \((3,2)\) and \((0,y)\) is
\[3^2+(y-2)^2\]

Answer 7

if you want them to be equal, set
\[25+(y+2)^2=9+(y-2)^2\] and solve for \(y\)