Find the point on the y-axis which is equidistant from A (-5, -2) and B (3, 2)

Question

anonymous · Answer

hint: if it is on the $y$ axis it looks like $(0,y)$

anonymous · Answer

A's y-coordinate is -2
B's y-coordinate is 2

The midway point between -2 and 2 is 0.

anonymous · Answer

hmmm i think maybe you need other work

anonymous · Answer

the square of the distance between $(-5,-2)$ and $(0,y)$ is 
$$5^2+(y+2)^2$$

anonymous · Answer

Oh whoops. Didn't read the question fully. Ill let this fine person help you. I trust he can lead you to a correct answer. (I see what I did. Simple mistakes getcha)

anonymous · Answer

and the square of the distance between $(3,2)$ and $(0,y)$ is 
$$3^2+(y-2)^2$$

anonymous · Answer

if you want them to be equal, set 
$$25+(y+2)^2=9+(y-2)^2$$ and solve for $y$